C Program which returns the next position of the character argument in the string, each time it is called

Function which takes string and a character as input and returns the next position of character each time it is called

Today we'll define a function with following properties:-

1. Return type of the function will be int i.e. the function will return an integer value.
2. Function will accept two arguments.
3. One of the argument will be a char and another char array.

Now let us try to understand our purpose with the help of an example......

Suppose our input string is: The domain name of this website is www.cspassion.com

and Suppose our input character is: 'i'

Then our function should do the following...

After 1st call-> 9

After 2nd call->22

After 3rd call->29

After 4th call->33

After 5th call->46

There by if any more calls are made to the function then "No more occurrences" kind of message should be displayed.

Hope the purpose is understood, lets give it a shot before proceeding further......

Logic:

1. We'll use infinite while loop which will include switch-case control inside it.
2. One case will make a call to function and another will bt he exit case.
3. We'll use static variable as function's local variable so that its previous value is not lost whenever a new call is made to the function.

Output String-Character position Program

Source code

#include<stdio.h>

int get_position(char linput,char linput1[100])

{

    static int count=0;

    while(linput1[count]!=linput)

    {

        count=count+1;

    }

       count=count+1;

    return count;

}

void main()

{

    int count=0,pocket,choice,i,count1=0;

    char input,input1[100];

    printf("Enter the String\n");

    fflush(stdin);

    fgets(input1,sizeof(input1),stdin);

    printf("\nEnter the character whose position you want to return:");

    scanf("%c",&input);

    for(i=0;i<strlen(input1);i++)

    {

        if(input1[i]==input)

            count1++;

    }

    while(1)

    {

    printf("\nEnter 1 to call the function,it would be your call '%d'\n",count+1);

    printf("\nEnter 2 for exit\n");

    printf("Enter your choice:");

    scanf("%d",&choice);

        switch(choice)

        {

            case 1:

                count=count+1;

                if(count<=count1)

                {

                fflush(stdin);

                pocket=get_position(input,input1);

                printf("\nAfter call %d,the position is %d\n",count,pocket);

                }

                else{

                    printf("No more occurrences of the specified character");

                    exit(1);

                }

                break;

            case 2:

                exit(1);

                break;

            default:

                printf("Invalid input\n");

                break;

        }

    }

}